Question

what is the weight - volume percent concentration of a 90.0% (\\(\frac{w}{v}\\)) solution of vitamin c after each of the following dilutions? be sure each of your answer entries has the correct number of significant figures.
part 1 of 2
100 ml diluted to 200. ml.
part 2 of 2
0.480 l diluted to 2400. ml.

Explanation:

Part 1 of 2

Step1: Use the dilution formula \(C_1V_1 = C_2V_2\)

Let \(C_1 = 90.0\%\), \(V_1=100\space mL\), \(V_2 = 200\space mL\). We need to find \(C_2\).
From \(C_1V_1 = C_2V_2\), we can express \(C_2=\frac{C_1V_1}{V_2}\).

Step2: Substitute the values into the formula

\(C_2=\frac{90.0\%\times100\space mL}{200\space mL}\)

$$
LATEXBLOCK0
$$

Part 2 of 2

Step1: Use the dilution formula \(C_1V_1 = C_2V_2\)

First, convert \(0.480\space L\) to \(480\space mL\). Let \(C_1 = 90.0\%\), \(V_1 = 480\space mL\), \(V_2=2400\space mL\). We need to find \(C_2\).
From \(C_1V_1 = C_2V_2\), we can express \(C_2=\frac{C_1V_1}{V_2}\).

Step2: Substitute the values into the formula

\(C_2=\frac{90.0\%\times480\space mL}{2400\space mL}\)

$$
LATEXBLOCK1
$$

Answer:

Part 1 of 2: \(45.0\%\)
Part 2 of 2: \(18.0\%\)