Question

1. what volume of vinegar contains 75.6 g of acetic acid if the solution is 0.889 m?

Explanation:

Step1: Calculate the molar mass of acetic acid ($\text{CH}_3\text{COOH}$)

The molar mass of $\text{C}$ is $12.01\ \text{g/mol}$, of $\text{H}$ is $1.008\ \text{g/mol}$, and of $\text{O}$ is $16.00\ \text{g/mol}$.
For $\text{CH}_3\text{COOH}$:

$$
LATEXBLOCK0
$$

Step2: Calculate the number of moles of acetic acid

Using the formula $n=\frac{m}{M}$, where $m = 75.6\ \text{g}$ and $M=60.052\ \text{g/mol}$

$$ n=\frac{75.6\ \text{g}}{60.052\ \text{g/mol}}\approx1.26\ \text{mol} $$

Step3: Calculate the volume of the solution

Using the formula $V=\frac{n}{C}$, where $n = 1.26\ \text{mol}$ and $C = 0.889\ \text{M}$

$$ V=\frac{1.26\ \text{mol}}{0.889\ \text{mol/L}}\approx1.42\ \text{L} $$

Answer:

The volume of vinegar is approximately $1.42\ \text{L}$.