Question

what volume, in liters, of 0.023 m nh4no3 solution can be made using 25 g nh4no3? nh4no3: 80.043 g/mol

Explanation:

Step1: Calculate moles of NH₄NO₃

Moles = mass / molar mass. Mass is 25 g, molar mass is 80.043 g/mol. So moles = \( \frac{25\ g}{80.043\ g/mol} \approx 0.3123\ mol \).

Step2: Use molarity formula to find volume

Molarity (M) = moles / volume (L). Rearranged, volume = moles / M. M is 0.023 M, moles is 0.3123 mol. So volume = \( \frac{0.3123\ mol}{0.023\ M} \approx 13.58\ L \).

Answer:

Approximately 13.6 L (or more precisely ~13.58 L)