what volume of a 1.25 m potassium fluoride (kf) solution would be needed to make 455 ml of a 0.838 m solution by dilution?

? ml of 1.25 m kf

be sure to give your answer in the requested units.

Question

what volume of a 1.25 m potassium fluoride (kf) solution would be needed to make 455 ml of a 0.838 m solution by dilution?

?  ml of 1.25 m kf

be sure to give your answer in the requested units.

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Dilution Equation", "Dilution Calculations" ], "new_concepts": [], "current_concepts": [ "Dilution Equation", "Dilution Calculations", "Solution Concentration" ] } ## Identify the given values Using the **Dilution Calculations** knowledge point $$ \begin{aligned} M_1 &= 1.25\text{ M}\ M_2 &= 0.838\text{ M}\ V_2 &= 455\text{ mL} \end{aligned} $$ ## Apply the dilution formula Using the **Dilution Equation** knowledge point $$ \begin{aligned} M_1 V_1 &= M_2 V_2\ 1.25 \cdot V_1 &= 0.838 \cdot 455\ V_1 &= \frac{0.838 \cdot 455}{1.25}\ V_1 &= 305.028\text{ mL} \end{aligned} $$ ## Round to significant figures Using the **Dilution Calculations** knowledge point $$ \begin{aligned} V_1 \approx 305\text{ mL} \end{aligned} $$ What volume of a 1.25 M potassium fluoride (KF) solution would be needed to make 455 mL of a 0.838 M solution by dilution? 305 mL of 1.25 M KF { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Chemistry", "Dilution Calculations" ] }

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QUESTION IMAGE

Question

Explanation:

Identify the given values

Apply the dilution formula

Round to significant figures

Answer: