what is the vertex of this quadratic function?

(y = 2(x - 6)^2 - 4)

(?, )

Question

what is the vertex of this quadratic function?

(y = 2(x - 6)^2 - 4)

(?,  )

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Vertex of a Quadratic Function" ], "new_concepts": [ "Vertex Form of a Quadratic" ], "current_concepts": [ "Vertex of a Quadratic Function", "Vertex Form of a Quadratic" ] } ## Identify the vertex form of the quadratic equation Using the *Vertex of a Quadratic Function* knowledge point $$ y = a(x - h)^2 + k $$ ## Extract the coordinates of the vertex Using the *Vertex of a Quadratic Function* knowledge point $$ \begin{aligned} &y = 2(x - 6)^2 - 4\ &h = 6\ &k = -4\ &\text{Vertex: } (6, -4) \end{aligned} $$ What is the vertex of this quadratic function? $y = 2(x - 6)^2 - 4$ (6, -4) { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Vertex of a Quadratic Function" ] }

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QUESTION IMAGE

Question

Explanation:

Identify the vertex form of the quadratic equation

Extract the coordinates of the vertex

Answer: