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what is the vertex of this quadratic function? (y = 2(x - 6)^2 - 4) (?,…

Question

what is the vertex of this quadratic function?

(y = 2(x - 6)^2 - 4)

(?, )

Explanation:

Response

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"concepts_used": [
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<reasoning>

Identify the vertex form of the quadratic equation

Using the Vertex of a Quadratic Function knowledge point
\[
y = a(x - h)^2 + k
\]

Extract the coordinates of the vertex

Using the Vertex of a Quadratic Function knowledge point
\[

$$\begin{aligned} &y = 2(x - 6)^2 - 4\\ &h = 6\\ &k = -4\\ &\text{Vertex: } (6, -4) \end{aligned}$$

\]
</reasoning>

<answer>
What is the vertex of this quadratic function?

\(y = 2(x - 6)^2 - 4\)

(<blank>6</blank>, <blank>-4</blank>)
</answer>

<post_analysis>
{
"subject": "Mathematics",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Vertex of a Quadratic Function"
]
}
</post_analysis>

Answer:

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"step_cot",
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"explain_then_answer",
"tutor",
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],
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"Vertex of a Quadratic Function"
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"Vertex Form of a Quadratic"
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"Vertex of a Quadratic Function",
"Vertex Form of a Quadratic"
]
}
</pre_analysis>

<reasoning>

Identify the vertex form of the quadratic equation

Using the Vertex of a Quadratic Function knowledge point
\[
y = a(x - h)^2 + k
\]

Extract the coordinates of the vertex

Using the Vertex of a Quadratic Function knowledge point
\[

$$\begin{aligned} &y = 2(x - 6)^2 - 4\\ &h = 6\\ &k = -4\\ &\text{Vertex: } (6, -4) \end{aligned}$$

\]
</reasoning>

<answer>
What is the vertex of this quadratic function?

\(y = 2(x - 6)^2 - 4\)

(<blank>6</blank>, <blank>-4</blank>)
</answer>

<post_analysis>
{
"subject": "Mathematics",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Vertex of a Quadratic Function"
]
}
</post_analysis>