Question

what is the temperature of a 1.59 l flask containing 0.175 mol of ne at a pressure of 1.09 atm?
select the correct answer below:
829 k
217 k
336 k
121 k

Explanation:

Step1: Use the ideal gas law

$$PV = nRT$$
where \(P = 1.09\space atm\), \(V=1.59\space L\), \(n = 0.175\space mol\), \(R = 0.0821\space L\cdot atm/(mol\cdot K)\) (gas constant), and \(T\) is the temperature we want to find.

Step2: Rearrange the formula for \(T\)

$$T=\frac{PV}{nR}$$

Step3: Substitute the values

$$T=\frac{1.09\times1.59}{0.175\times0.0821}$$
$$T=\frac{1.7331}{0.0143675}$$

Step4: Calculate \(T\)

$$T\approx336\space K$$

Answer:

336 K