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Question
what is the solution to \\(\log_{5}(10x-1) = \log_{5}(9x+7)\\)?
\\(x = \frac{6}{19}\\)
\\(x = \frac{8}{19}\\)
\\(x = 7\\)
\\(x = 8\\)
Equate the arguments using the one-to-one property
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Solve for x
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Verify the solution in the original domain
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- (A) \(x = \frac{6}{19}\)
- (B) \(x = \frac{8}{19}\)
- (C) \(x = 7\)
- (D) \(x = 8\) (Correct answer)