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what is the solution to \\(\\log_{5}(10x-1) = \\log_{5}(9x+7)\\)? \\(x …

Question

what is the solution to \\(\log_{5}(10x-1) = \log_{5}(9x+7)\\)?

\\(x = \frac{6}{19}\\)

\\(x = \frac{8}{19}\\)

\\(x = 7\\)

\\(x = 8\\)

Explanation:

Equate the arguments using the one-to-one property

$$ LATEXBLOCK0 $$

Solve for x

$$ LATEXBLOCK1 $$

Verify the solution in the original domain

$$ LATEXBLOCK2 $$

Answer:

  • (A) \(x = \frac{6}{19}\)
  • (B) \(x = \frac{8}{19}\)
  • (C) \(x = 7\)
  • (D) \(x = 8\) (Correct answer)