Question

what are product of the reaction of lead(ii) nitrate with sodium chloride?
select all that apply.
□ na₂o
□ pbo
□ nano₃
□ pbcl₂

Explanation:

Step1: Identify Reaction Type

This is a double - displacement reaction. In double - displacement reactions, the general form is \(AB + CD
ightarrow AD+CB\), where the cations and anions of the two reactants switch places. For the reaction between lead(II) nitrate (\(Pb(NO_3)_2\)) and sodium chloride (\(NaCl\)), the lead (\(Pb^{2 +}\)) ion will combine with the chloride (\(Cl^-\)) ion and the sodium (\(Na^+\)) ion will combine with the nitrate (\(NO_3^-\)) ion.

Step2: Write the Chemical Equation

The unbalanced chemical equation for the reaction is \(Pb(NO_3)_2+NaCl
ightarrow NaNO_3 + PbCl_2\). Balancing the equation, we get \(Pb(NO_3)_2 + 2NaCl=2NaNO_3+PbCl_2\).

Step3: Determine the Products

From the balanced chemical equation, we can see that the products of the reaction between lead(II) nitrate and sodium chloride are sodium nitrate (\(NaNO_3\)) and lead(II) chloride (\(PbCl_2\)). The compounds \(Na_2O\) and \(PbO\) are not products of this double - displacement reaction.

Answer:

\(NaNO_3\), \(PbCl_2\) (the checkboxes corresponding to \(NaNO_3\) and \(PbCl_2\) should be selected)