Question

what is the ph of a solution with h⁺ = 1.25 × 10⁻¹⁰ m? use ph = - log h₃o⁺.

Explanation:

Step1: Sustituir el valor de \([H^+]\) en la fórmula de pH

$$pH = -\log(1.25\times10^{-10})$$

Step2: Aplicar la propiedad del logaritmo \(\log(ab)=\log(a)+\log(b)\)

$$pH = -(\log(1.25)+\log(10^{-10}))$$

Step3: Calcular \(\log(10^{-10})\) y \(\log(1.25)\)

Sabemos que \(\log(10^{-10})=- 10\) y \(\log(1.25)\approx0.0969\)
$$pH=- (0.0969 - 10)$$

Step4: Simplificar la expresión

$$pH=-0.0969 + 10$$
$$pH\approx9.90$$

Answer:

B. \(9.90\)