Question

1. what is the percent composition of na₂co₃?% na =% c =% o =

Explanation:

Step1: Calculate molar mass of \(Na_2CO_3\)

Atomic masses: \(Na = 22.99\space g/mol\), \(C = 12.01\space g/mol\), \(O = 16.00\space g/mol\)
\(Molar\space mass\space of\space Na_2CO_3=(2\times22.99)+12.01+(3\times16.00)\)
\(=45.98 + 12.01+48.00\)
\(=105.99\space g/mol\)

Step2: Calculate \(\%\space Na\)

\(\%\space Na=\frac{2\times22.99}{105.99}\times100\)
\(=\frac{45.98}{105.99}\times100\approx43.4\%\)

Step3: Calculate \(\%\space C\)

\(\%\space C=\frac{12.01}{105.99}\times100\approx11.3\%\)

Step4: Calculate \(\%\space O\)

\(\%\space O=\frac{3\times16.00}{105.99}\times100\)
\(=\frac{48.00}{105.99}\times100\approx45.3\%\)

Answer:

\(\%\space Na\approx43.4\%\), \(\%\space C\approx11.3\%\), \(\%\space O\approx45.3\%\)