Question

what is the oxidation number of nitrogen in nh₄cl?
-3
+3
+2
0

Explanation:

Step1: Recall oxidation rules

In a compound, the sum of oxidation numbers is zero. For \(NH_4Cl\), it dissociates into \(NH_4^+\) and \(Cl^-\). Chloride (\(Cl^-\)) has oxidation number \(-1\), so \(NH_4^+\) has oxidation number \(+1\) (since overall compound is neutral).

Step2: Let N's oxidation number be \(x\)

Hydrogen in \(NH_4^+\) has oxidation number \(+1\) (rule: H is +1 in compounds with non - metals). There are 4 H atoms. So for \(NH_4^+\): \(x + 4\times(+1)=+1\)

Step3: Solve for \(x\)

\(x + 4 = 1\), so \(x=1 - 4=-3\)

Answer:

-3 (corresponding to the option with -3)