Question

what is the molarity of a solution in which 1.20 mol of solute is dissolved in 3.00 l of solution?
0.400 m
15.0 m
3.60 m

1. m

Explanation:

Step1: Recall the formula for molarity

Molarity ($M$) is calculated as $M=\frac{n}{V}$, where $n$ is the number of moles of solute and $V$ is the volume of the solution in liters.

Step2: Substitute the given values into the formula

Given $n = 1.20\space mol$ and $V=3.00\space L$. Then $M=\frac{1.20\space mol}{3.00\space L}$.

Step3: Perform the division

$\frac{1.20}{3.00}=0.400$.

Answer:

A. $0.400\space M$