Question

what is the molarity of a solution with 49.6 g of nacl dissolved in 1.88 l of water? report your answer to 2 places past the decimal point.

Explanation:

Step1: Calculate the molar mass of NaCl

The molar mass of \(Na\) is \(22.99\space g/mol\) and the molar mass of \(Cl\) is \(35.45\space g/mol\). So, the molar mass of \(NaCl\), \(M = 22.99+35.45=58.44\space g/mol\)

Step2: Calculate the number of moles of NaCl

Using the formula \(n=\frac{m}{M}\), where \(m = 49.6\space g\) and \(M = 58.44\space g/mol\). Then \(n=\frac{49.6}{58.44}\approx0.849\space mol\)

Step3: Calculate the molarity of the solution

Using the formula \(C=\frac{n}{V}\), where \(n = 0.849\space mol\) and \(V = 1.88\space L\). Then \(C=\frac{0.849}{1.88}\approx0.45\space mol/L\)

Answer:

\(0.45\)