Question

what is the molarity of 0.500 l of naoh solution if it contains 6.00 g of naoh?

Explanation:

Step1: Calculate the molar mass of NaOH

The molar mass of \(Na\) is \(22.99\ g/mol\), \(O\) is \(16.00\ g/mol\), and \(H\) is \(1.01\ g/mol\).

$$M_{NaOH}=22.99 + 16.00+1.01=40.00\ g/mol$$

Step2: Calculate the number of moles of NaOH

Use the formula \(n=\frac{m}{M}\), where \(m = 6.00\ g\) and \(M = 40.00\ g/mol\)

$$n=\frac{6.00\ g}{40.00\ g/mol}=0.150\ mol$$

Step3: Calculate the molarity of the solution

Use the formula \(M=\frac{n}{V}\), where \(n = 0.150\ mol\) and \(V=0.500\ L\)

$$M=\frac{0.150\ mol}{0.500\ L}=0.300\ M$$

Answer:

\(0.300\ M\)