Question

1. what is the molality of a 13.82 % by mass glucose solution? the molar mass of glucose, c₆h₁₂o₆ is 180.16 g/mol. a. 0.1604 m b. 0.7671 m c. 0.8901 m d. 4.529 m e. 28.90 m

Explanation:

Step1: Define mass of solution and solute

Assume 100 g of solution (since % by mass is mass solute/mass solution ×100). So mass of glucose (solute) = 13.82 g, mass of solvent (water) = 100 - 13.82 = 86.18 g = 0.08618 kg.

Step2: Calculate moles of glucose

Moles of glucose = mass / molar mass = \( \frac{13.82\ \text{g}}{180.16\ \text{g/mol}} \approx 0.07671\ \text{mol} \).

Step3: Calculate molality

Molality (m) = moles of solute / kg of solvent = \( \frac{0.07671\ \text{mol}}{0.08618\ \text{kg}} \approx 0.8901\ m \).

Answer:

C. 0.8901 m