Question

what is the maximum number of electrons in the second principal energy level
1s
2s 2p
3s 3p 3d
4s 4p 4d 4f
5s 5p 5d 5f
6s 6p 6d
7s 7p
4
6
2
8
question 15
0.4 pts
in the formula c = λ*v, what is v
brightness
wavelength
frequency
speed of light

Explanation:

Step1: Analyze second - energy level sub - shells

The second principal energy level ($n = 2$) has two sub - shells: $2s$ and $2p$. The $s$ sub - shell has 1 orbital and the $p$ sub - shell has 3 orbitals.

Step2: Calculate electrons per sub - shell

Each orbital can hold a maximum of 2 electrons. The $2s$ sub - shell with 1 orbital can hold $1\times2=2$ electrons. The $2p$ sub - shell with 3 orbitals can hold $3\times2 = 6$ electrons.

Step3: Find total electrons in $n = 2$

The total number of electrons in the second principal energy level is $2 + 6=8$ electrons.

For the second question:
The formula $c=\lambda\times
u$ (where $c$ is the speed of light, $\lambda$ is the wavelength and $
u$ is the frequency of light). So $
u$ represents frequency.

Answer:

First question: O 8
Second question: O frequency