Question

what is the mass of 2.40 x 10^{24} molecules of c_{3}h_{8}? (1 mole c_{3}h_{8} = 44.11 g) (1 mole c_{3}h_{8} = 6.02 x 10^{23} molecules) ? g c_{3}h_{8}

Explanation:

Step1: Calculate the number of moles

Use the formula \(n=\frac{N}{N_A}\), where \(N = 2.40\times 10^{24}\) molecules and \(N_A=6.02\times 10^{23}\text{ molecules/mol}\).
\(n=\frac{2.40\times 10^{24}}{6.02\times 10^{23}}\)
\(n\approx 3.99\) mol

Step2: Calculate the mass

Use the formula \(m = n\times M\), where \(n = 3.99\) mol and \(M = 44.11\) g/mol.
\(m=3.99\times44.11\)
\(m\approx176\) g

Answer:

\(176\) g