Question

1. what is the mass of 5.34×10²⁰ particles of c₂h₆?

Explanation:

Step1: Calculate molar mass of \(C_2H_6\)

Molar mass of \(C = 12.01\ g/mol\), molar mass of \(H=1.008\ g/mol\).
For \(C_2H_6\), \(M=(2\times12.01 + 6\times1.008)\ g/mol=(24.02+6.048)\ g/mol = 30.068\ g/mol\)

Step2: Calculate the number of moles

Use Avogadro's number \(N_A = 6.022\times 10^{23}\ particles/mol\).
Number of moles \(n=\frac{N}{N_A}\), where \(N = 5.34\times 10^{20}\ particles\)
\(n=\frac{5.34\times 10^{20}}{6.022\times 10^{23}}\ mol\approx8.87\times 10^{-4}\ mol\)

Step3: Calculate the mass

Use the formula \(m = n\times M\)
\(m=(8.87\times 10^{-4}\ mol)\times30.068\ g/mol\approx0.0267\ g\)

Answer:

\(0.0267\ g\)