1. what kind of bond am i?
use the type of elements present to determine the type of bond (ionic, metallic, or covalent)
that each would form.
a. n and o
________________________
b. ca and c
________________________
c. be and f
________________________
d. c and i
________________________
2. complete the table by identifying the type of bond and writing the name for each
compound.
3. how many al³+ ions would pair with the sulfide ion, s²-? think in terms of unit by
charge, like the card activity had you do. for example, fe₂o₃ in the table above has 2 fe³+
ions and 3 o²- ions.
4. what would be the name of the substance formed in #3?
5. draw the basic lewis structure of oxygen gas, o₂, below:

Question

Accepted Answer

# 1.
## a.
### Brief Explanations:
Nitrogen (N) and oxygen (O) are both non - metals. Non - metals tend to share electrons to form covalent bonds.
### Answer:
Covalent

## b.
### Brief Explanations:
Calcium (Ca) is a metal and carbon (C) is a non - metal. Metals and non - metals usually form ionic bonds where electrons are transferred from the metal to the non - metal.
### Answer:
Ionic

## c.
### Brief Explanations:
Beryllium (Be) is a metal and fluorine (F) is a non - metal. The transfer of electrons from the metal (Be) to the non - metal (F) occurs, which is characteristic of ionic bond formation.
### Answer:
Ionic

## d.
### Brief Explanations:
Carbon (C) and iodine (I) are both non - metals. Non - metals share electrons to form covalent bonds.
### Answer:
Covalent

# 2.
## For $CS_3$
### Brief Explanations:
Carbon (C) and sulfur (S) are non - metals. Non - metals form covalent bonds. The name is based on the elements: carbon trisulfide (prefix “tri - ” for three sulfur atoms).
### Answer:
Bond Type: Covalent; Name: Carbon trisulfide

## For $CaBr_2$
### Brief Explanations:
Calcium (Ca) is a metal and bromine (Br) is a non - metal. Metals and non - metals form ionic bonds. The name is calcium bromide (the metal name first, then the non - metal with - ide ending).
### Answer:
Bond Type: Ionic; Name: Calcium bromide

## For $Fe_2O_3$
### Brief Explanations:
Iron (Fe) is a metal and oxygen (O) is a non - metal. They form ionic bonds. The name is iron(III) oxide (using Roman numeral for the charge of Fe, which is + 3 in this case).
### Answer:
Bond Type: Ionic; Name: Iron(III) oxide

## For $Ni$
### Brief Explanations:
Nickel (Ni) is a metal. Metals have metallic bonds (a sea of delocalized electrons around metal cations). The name is nickel (the element name).
### Answer:
Bond Type: Metallic; Name: Nickel

# 3.
## Step - by - Step Format
### Explanation:
## Step 1: Set up the charge balance equation
Let the number of $Al^{3 + }$ ions be $x$ and the number of $S^{2-}$ ions be $y$. The total positive charge should equal the total negative charge. So $3x=2y$. We want to find the smallest whole - number ratio. When $y = 3$, then $3x=2\times3$.
## Step 2: Solve for $x$
From $3x = 6$, we can divide both sides by 3. So $x=\frac{6}{3}=2$

### Answer:
2

# 4.
## Answer - Explanation Format
### Brief Explanations:
The compound is formed from $Al^{3+}$ and $S^{2 - }$ ions. The metal (Al) is named first, then the non - metal (S) with an - ide ending. Using the ratio from question 3 ($Al_2S_3$), the name is based on the ions: aluminum sulfide.
### Answer:
Aluminum sulfide

# 5.
## Answer - Explanation Format
### Brief Explanations:
Oxygen ($O$) has 6 valence electrons. In $O_2$, each $O$ atom shares two pairs of electrons (a double bond) to complete its octet. The Lewis structure has two $O$ atoms with a double bond ($O = O$) and two lone pairs on each $O$ atom.
### Answer:
$:\!O\!=\!O:$ (with two lone pairs on each $O$ atom represented as pairs of dots around each $O$ atom)

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