Question

what is the final concentration of a 508.43 ml solution that was prepared from 5.87 ml of a 11.2 m stock solution? report your answer to 2 decimal places.

Explanation:

Step1: Write the dilution formula

The formula for dilution is \(C_1V_1 = C_2V_2\), where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.

Step2: Rearrange the formula to solve for \(C_2\)

\(C_2=\frac{C_1V_1}{V_2}\)

Step3: Substitute the given values

Given \(C_1 = 11.2\space M\), \(V_1=5.87\space mL\), and \(V_2 = 508.43\space mL\).
\(C_2=\frac{11.2\times5.87}{508.43}\)
First, calculate \(11.2\times5.87 = 65.744\)
Then, \(C_2=\frac{65.744}{508.43}\approx0.13\space M\)

Answer:

\(0.13\)