Question

what else is produced during the combustion of butane, c₄h₁₀?
2c₄h₁₀ + 13o₂ → 8_______ + 10h₂o
○ h₂o
○ c₄h₁₀
○ co₂
○ o₂

Explanation:

Step1: Apply Law of Conservation of Mass

In a chemical reaction, the number of each type of atom must be the same on both sides. For carbon (C): left side has \(2\times4 = 8\) C atoms. So the unknown product must have C atoms.

Step2: Analyze Oxygen and Hydrogen

Hydrogen (H): left has \(2\times10 = 20\) H, right \(10\times2 = 20\) H (balanced). Oxygen (O): left \(13\times2 = 26\) O, right \(10\times1 = 10\) O from \(H_2O\). So unknown needs \(26 - 10 = 16\) O.

Step3: Determine the Product

Each \(CO_2\) has 1 C and 2 O. 8 \(CO_2\) gives 8 C (matches left) and \(8\times2 = 16\) O (matches needed). So the product is \(CO_2\).

Answer:

\(CO_2\) (the option with \(CO_2\))