Question

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x give the chemical formula for the following compound:
x tin (iv) oxalate

Explanation:

Step1: Determine the ion of tin

Tin (IV) has a charge of \(Sn^{4+}\).

Step2: Determine the ion of oxalate

Oxalate ion is \(C_{2}O_{4}^{2 -}\).

Step3: Balance the charges

To balance the charges, we need \(2\) oxalate ions (\(2\times(- 2)=-4\)) for \(1\) tin (IV) ion (\(+4\)).

Answer:

\(Sn(C_{2}O_{4})_{2}\)