Question

if the volume of the gas stays constant and the moles of gas in the container stays constant (like what happens in a rigid container), what would the combined gas law simplify to?

p₁v₁ = p₂v₂

p₁t₁ = p₂t₂

v₁t₁ = v₂t₂

p₁/t₁ = p₂/t₂

Explanation:

Step1: Recall the combined gas law

The combined gas law is \(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\), where \(P\) is pressure, \(V\) is volume, and \(T\) is temperature.

Step2: Substitute \(V_1 = V_2\) (constant volume)

Since \(V_1 = V_2\), we can cancel out \(V_1\) and \(V_2\) in the combined gas law \(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\). After canceling \(V\) (because \(V_1 = V_2
eq0\)), we get \(\frac{P_1}{T_1}=\frac{P_2}{T_2}\).

Answer:

\(P_1/T_1 = P_2/T_2\) (the last option)