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if v1 and v2 are given in ml and p1 is given in atm, and you are asked …

Question

if v1 and v2 are given in ml and p1 is given in atm, and you are asked to calculate p2, you will need to convert v1 and v2 in l before calculating p2

Explanation:

Step1: Recall Boyle's Law

Boyle's Law is \(P_1V_1 = P_2V_2\). The units of volume just need to be consistent (both in mL or both in L). Since \(P_1\) is in atm (a pressure unit), and we are calculating \(P_2\) (also a pressure unit), as long as \(V_1\) and \(V_2\) have the same volume unit (regardless of whether it is mL or L), the ratio \(\frac{V_1}{V_2}\) is dimensionless. So we don't need to convert \(V_1\) and \(V_2\) from mL to L.

Answer:

False