Question

using the puzzle pieces provided (and by duplicating them), create three different ionic compounds containing at least one polyatomic ion.
be sure to name each compound you create (use the names on the previous slide to help!)

Explanation:

Step1: Determine the formula for Compound 2

We have \(Al^{3 +}\) and \(PO_{4}^{3-}\). Using the criss - cross method (the magnitude of the charge of one ion becomes the subscript of the other ion). Since the charge of \(Al^{3+}\) is \(3+\) and the charge of \(PO_{4}^{3 -}\) is \(3-\), the formula is \(AlPO_{4}\).

Step2: Determine the formula for Compound 3

We have \(NH_{4}^{+}\) and \(PO_{4}^{3-}\). Using the criss - cross method, the charge of \(NH_{4}^{+}\) is \(1+\) and the charge of \(PO_{4}^{3 -}\) is \(3-\). So the formula is \((NH_{4})_{3}PO_{4}\)

Answer:

Compound 2 formula: \(AlPO_{4}\) (aluminum phosphate)
Compound 3 formula: \((NH_{4})_{3}PO_{4}\) (ammonium phosphate)