Question

using the provided table, determine the molar enthalpy (in kj/mol) for the reaction c(s) + co₂(g) → 2co(g)
substance\tδhf° (kj/mol)
c(s)\t0
co₂(g)\t-393.5
co(g)\t-110.5
answer:
kj/mol

Explanation:

Step1: <Formula for molar enthalpy>

$$\Delta H_{reaction}=\sum n\Delta H_{f(products)}-\sum m\Delta H_{f(reactants)}$$

Step2: <Substitute values>

For the reaction \(C(s)+CO_{2}(g)\to2CO(g)\), \(n = 2\) (for \(CO\)), \(m_1 = 1\) (for \(C\)) and \(m_2 = 1\) (for \(CO_{2}\)).
\(\Delta H_{reaction}=(2\times(- 110.5))-(0+(-393.5))\)

Step3: <Calculate>

$$
LATEXBLOCK0
$$

Answer:

\(172.5\)