Question

using the
as\ idea, how many electrons are \available\ for the compound h₂s? n = 12 12 24 8

Explanation:

Step1: Determine the number of valence electrons for each atom

• Hydrogen (\(H\)) has \(1\) valence electron. There are \(2\) \(H\) atoms, so total valence electrons from \(H\) is \(2\times1 = 2\).
• Sulfur (\(S\)) has \(6\) valence electrons.

Step2: Calculate the available electrons (\(A\))

The formula for \(A\) (available electrons) in the NAS ( \(N = A+S\), where \(N\) is the octet/duplet electrons and \(S\) is the shared electrons) context, but if we just consider the valence - electron sum (which is related to the available electrons concept in simple bonding electron - count), the sum of valence electrons of \(H_2S\) is \(2 + 6=8\).

Answer:

\(8\)