Question

use the periodic table to write the electron configuration for barium (ba) in noble - gas notation. ba: 6s²

Explanation:

Step1: Find the noble gas before barium

The noble gas before barium (Ba) in the periodic table is xenon (Xe).

Step2: Write the electron configuration

Barium has an atomic number of 56. Xenon has an atomic number of 54. So, the remaining 2 electrons go into the 6s orbital.

Answer:

$$ [\text{Xe}]6s^{2} $$