Question

use the chart to determine if the following compound forms an ionic, polar covalent or non - polar covalent bond: o₂

Explanation:

Step1: Determine electronegativity difference

For \(O_2\), both atoms are oxygen. The electronegativity of oxygen is the same. So the electronegativity difference \(\Delta EN=0\) (since \(EN_{O}-EN_{O} = 0\)).

Step2: Classify the bond

• Ionic bonds have \(\Delta EN> 1.7\).
• Polar covalent bonds have \(0<\Delta EN\leq1.7\).
• Non - polar covalent bonds have \(\Delta EN = 0\).

Since \(\Delta EN = 0\) for \(O_2\), it forms a non - polar covalent bond.

Answer:

Non - Polar Covalent