Question

if the theoretical yield of the reaction below corresponds to 99.2 g and the actual yield was 60.9 g, calculate the percent yield.
given: li₂o + h₂o → 2 lioh
a 61.4 %
b 71.8 %
c 16.0 %
d 38.0 %

Explanation:

Step1: Recall the formula for percent yield

Percent yield = $\frac{\text{actual yield}}{\text{theoretical yield}}\times100\%$

Step2: Substitute the given values into the formula

Here, actual yield = $60.9\ g$ and theoretical yield = $99.2\ g$
Percent yield = $\frac{60.9}{99.2}\times100\%$
Calculate $\frac{60.9}{99.2}\approx0.614$
Then $0.614\times100\% = 61.4\%$

Answer:

A. 61.4%