Question

test: covalent compounds
which of these is the correct lewis structure for sibr₄?
a) :br:
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br - si - br
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:br:
b) br
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br = si = br
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br
c) br = si = br
d) :br:
|
:br - si - br:
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:br:
oa
ob
oc
od

Explanation:

• In a Lewis structure, each atom should have a complete octet (except for some exceptions).
• Silicon (\(Si\)) has 4 valence electrons and each bromine (\(Br\)) has 7 valence electrons.
• In \(SiBr_4\), \(Si\) forms single bonds with four \(Br\) atoms. Each \(Br\) atom has three lone pairs of electrons to complete its octet.
• Option \(a\) is incorrect because the \(Br\) atoms do not have complete octets (missing lone pairs).
• Option \(b\) and \(c\) are incorrect because \(Si\) and \(Br\) do not form double bonds in \(SiBr_4\).

Answer:

D.