QUESTION IMAGE
Question
the sum of the exterior angles of any polygon is always equal to 360
exterior angles: non - regular polygons
find the value of x.
- x=
- x=
- x=
- x=
exterior angles: regular polygons
find the measure of one exterior angle for the regular polygon with n sides.
- quadrilateral
- octagon
- 16 - gon
1)
Step1: Use the sum of exterior angles formula
The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(75^{\circ},44^{\circ},65^{\circ},54^{\circ},76^{\circ},x^{\circ}\).
Step2: Simplify the left - hand side
2)
Step1: Use the sum of exterior angles formula
The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(85^{\circ},71^{\circ},48^{\circ},2x^{\circ},3x^{\circ}\).
Step2: Combine like terms
3)
Step1: Use the sum of exterior angles formula
The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(60^{\circ},80^{\circ},110^{\circ},70^{\circ},x^{\circ}\).
Step2: Simplify the left - hand side
4)
Step1: Use the sum of exterior angles formula
The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(110^{\circ},70^{\circ},70^{\circ},x^{\circ}\).
Step2: Simplify the left - hand side
9)
Step1: Use the formula for exterior angle of a regular polygon
The formula for the measure of an exterior angle of a regular polygon is \(\frac{360^{\circ}}{n}\). For a quadrilateral \(n = 4\).
10)
Step1: Use the formula for exterior angle of a regular polygon
For an octagon \(n = 8\).
11)
Step1: Use the formula for exterior angle of a regular polygon
For a \(16 -\)gon \(n = 16\).
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- \(x = 46\)
- \(x = 31.2\)
- \(x = 40\)
- \(x = 110\)
- \(90^{\circ}\)
- \(45^{\circ}\)
- \(22.5^{\circ}\)