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the sum of the exterior angles of any polygon is always equal to 360 ex…

Question

the sum of the exterior angles of any polygon is always equal to 360
exterior angles: non - regular polygons
find the value of x.

  1. x=
  2. x=
  3. x=
  4. x=

exterior angles: regular polygons
find the measure of one exterior angle for the regular polygon with n sides.

  1. quadrilateral
  2. octagon
  3. 16 - gon

Explanation:

1)

Step1: Use the sum of exterior angles formula

The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(75^{\circ},44^{\circ},65^{\circ},54^{\circ},76^{\circ},x^{\circ}\).

$$75 + 44+65 + 54+76+x=360$$
Step2: Simplify the left - hand side
$$ (75 + 44)+(65 + 54)+(76+x)=360$$
$$119+119+(76+x)=360$$
$$238+(76+x)=360$$
$$x=360-(238 + 76)$$
$$x = 46$$

2)

Step1: Use the sum of exterior angles formula

The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(85^{\circ},71^{\circ},48^{\circ},2x^{\circ},3x^{\circ}\).

$$85+71 + 48+2x+3x=360$$
Step2: Combine like terms
$$204 + 5x=360$$
$$5x=360 - 204$$
$$5x=156$$
$$x = 31.2$$

3)

Step1: Use the sum of exterior angles formula

The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(60^{\circ},80^{\circ},110^{\circ},70^{\circ},x^{\circ}\).

$$60+80 + 110+70+x=360$$
Step2: Simplify the left - hand side
$$320+x=360$$
$$x=360 - 320$$
$$x = 40$$

4)

Step1: Use the sum of exterior angles formula

The sum of exterior angles of a polygon is \(360^{\circ}\). Let the exterior angles be \(110^{\circ},70^{\circ},70^{\circ},x^{\circ}\).

$$110+70 + 70+x=360$$
Step2: Simplify the left - hand side
$$250+x=360$$
$$x=360 - 250$$
$$x = 110$$

9)

Step1: Use the formula for exterior angle of a regular polygon

The formula for the measure of an exterior angle of a regular polygon is \(\frac{360^{\circ}}{n}\). For a quadrilateral \(n = 4\).

$$ \text{Exterior angle}=\frac{360^{\circ}}{4}=90^{\circ}$$

10)

Step1: Use the formula for exterior angle of a regular polygon

For an octagon \(n = 8\).

$$ \text{Exterior angle}=\frac{360^{\circ}}{8}=45^{\circ}$$

11)

Step1: Use the formula for exterior angle of a regular polygon

For a \(16 -\)gon \(n = 16\).

$$ \text{Exterior angle}=\frac{360^{\circ}}{16}=22.5^{\circ}$$

Answer:

  1. \(x = 46\)
  2. \(x = 31.2\)
  3. \(x = 40\)
  4. \(x = 110\)
  5. \(90^{\circ}\)
  6. \(45^{\circ}\)
  7. \(22.5^{\circ}\)