Question

d. in the space below, write the noble gas (abbreviated) electron configurations of the following elements: ag: silver bi: bismuth

Explanation:

Step1: Determine noble - gas core for Ag

Silver (Ag) has an atomic number of 47. The nearest noble gas with a lower atomic number is Kr (atomic number 36).

Step2: Write electron configuration after noble - gas core

After Kr, we need to account for 47 - 36=11 more electrons. The electron configuration is $[Kr]4d^{10}5s^{1}$.

Step3: Determine noble - gas core for Bi

Bismuth (Bi) has an atomic number of 83. The nearest noble gas with a lower atomic number is Xe (atomic number 54).

Step4: Write electron configuration after noble - gas core

After Xe, we need to account for 83 - 54 = 29 more electrons. The electron configuration is $[Xe]4f^{14}5d^{10}6s^{2}6p^{3}$.

Answer:

Ag: $[Kr]4d^{10}5s^{1}$
Bi: $[Xe]4f^{14}5d^{10}6s^{2}6p^{3}$