Question

1 = sp³; 2 = sp²; 3 = sp²; 4 = sp³; 5 = sp²
1 = sp²; 2 = sp³; 3 = sp³; 4 = sp³; 5 = sp³
1 = sp²; 2 = sp³; 3 = sp³; 4 = sp; 5 = sp
1 = sp³; 2 = sp³; 3 = sp³; 4 = sp³; 5 = sp³
1 = sp³; 2 = sp; 3 = sp³; 4 = sp; 5 = sp

Explanation:

Step1: Determine hybridization of atom 1

Atom 1 is part of a double - bonded carbon in the ring. For a carbon with a double bond, the hybridization is \(sp^{2}\).

Step2: Determine hybridization of atom 2

Atom 2 is a saturated carbon (single - bonded to other atoms). Saturated carbons have \(sp^{3}\) hybridization.

Step3: Determine hybridization of atom 3

Atom 3 is a saturated carbon (single - bonded to other atoms). Saturated carbons have \(sp^{3}\) hybridization.

Step4: Determine hybridization of atom 4

Atom 4 is part of a \(-OH\) group attached to a saturated carbon. The oxygen in \(-OH\) has \(sp^{3}\) hybridization (it has two lone pairs and two bonding pairs in a tetrahedral - like arrangement).

Step5: Determine hybridization of atom 5

Atom 5 is an oxygen in a single - bonded \(C - O\) (ether group). The oxygen has \(sp^{3}\) hybridization (two lone pairs and two bonding pairs in a tetrahedral - like arrangement).

Answer:

\(1 = sp^{2};2 = sp^{3};3 = sp^{3};4 = sp^{3};5 = sp^{3}\)