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Question
solve for the remaining sides and angles if possible (if not, answer dne in all answer boxes). as in the text. (a,a), (b,b), and (c,c) are angle - side opposite pairs. round to one decimal places, if necessary. a = 32, b = 32, c = 32
Step1: Recall the property of an equilateral triangle
In an equilateral triangle, all angles are equal.
Step2: Use the angle - sum property of a triangle
The sum of angles in a triangle is \(180^{\circ}\). Let each angle be \(x\). Then \(x + x+x=180^{\circ}\), i.e., \(3x = 180^{\circ}\).
Step3: Solve for \(x\)
Dividing both sides of \(3x = 180^{\circ}\) by \(3\), we get \(x=\frac{180^{\circ}}{3}=60^{\circ}\).
Since \(a = 32\), \(b = 32\), \(c = 32\) (given side - lengths)
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\(A = 60^{\circ}\), \(B = 60^{\circ}\), \(C = 60^{\circ}\), \(a = 32\), \(b = 32\), \(c = 32\)