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solve for the remaining sides and angles if possible (if not, answer dn…

Question

solve for the remaining sides and angles if possible (if not, answer dne in all answer boxes). as in the text. (a,a), (b,b), and (c,c) are angle - side opposite pairs. round to one decimal places, if necessary. a = 32, b = 32, c = 32

Explanation:

Step1: Recall the property of an equilateral triangle

In an equilateral triangle, all angles are equal.

Step2: Use the angle - sum property of a triangle

The sum of angles in a triangle is \(180^{\circ}\). Let each angle be \(x\). Then \(x + x+x=180^{\circ}\), i.e., \(3x = 180^{\circ}\).

Step3: Solve for \(x\)

Dividing both sides of \(3x = 180^{\circ}\) by \(3\), we get \(x=\frac{180^{\circ}}{3}=60^{\circ}\).

Since \(a = 32\), \(b = 32\), \(c = 32\) (given side - lengths)

Answer:

\(A = 60^{\circ}\), \(B = 60^{\circ}\), \(C = 60^{\circ}\), \(a = 32\), \(b = 32\), \(c = 32\)