Question

a solution is prepared by dissolving 2 g of kcl in 100 g of h₂o. in this solution, h₂o is the ionic compound. solution. solid. solvent. solute. question 4 (1 point) the mass/volume percent concentration refers to grams of solute in 100 ml of solution. grams of solute in 100 ml of solvent. grams of solute in 1 l of solvent. grams of solvent in 100 ml of solution. grams of solute in 1 l of solution. question 5 (1 point) water is a polar solvent and hexane (c₆h₁₄) is a nonpolar solvent. which of the following correctly describes the solubility of the solute? octane (nonpolar), soluble in water

Explanation:

• For the first question: A solution has a solute (the substance being dissolved, here KCl) and a solvent (the substance doing the dissolving, here \(H_2O\)). \(H_2O\) is not an ionic compound (KCl is), not the solution itself (the combination of KCl and \(H_2O\) is the solution), not a solid (it's a liquid), and not the solute (KCl is the solute).
• For the second question: The mass/volume percent concentration is defined as grams of solute per 100 mL of solution (\(\text{mass/volume}\%=\frac{\text{mass of solute (g)}}{\text{volume of solution (mL)}}\times100\)).
• For the third (partial) question: According to the "like - dissolves - like" principle, non - polar solutes dissolve in non - polar solvents and polar solutes dissolve in polar solvents. Octane (non - polar) should be soluble in hexane (non - polar) and not in water (polar).

Answer:

• First question: solvent
• Second question: grams of solute in 100 mL of solution
• Third (partial) question: octane (non - polar) is not soluble in water (since it should follow the like - dissolves - like principle, non - polar in non - polar (hexane) and polar in polar (water))