Question

sn
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s²2p² should be entered as he2s^22p^2.

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Explanation:

Step1: Determine the atomic number of Sn

Tin (Sn) has an atomic number of 50.

Step2: Find the noble gas core

The noble gas before Sn is Kr (atomic number 36).

Step3: Write the remaining electrons

After Kr, we have \(50 - 36=14\) electrons. The electron configuration after Kr is \(4d^{10}5s^{2}5p^{2}\)

Answer:

$$ [Kr]4d^{\wedge}105s^{\wedge}25p^{\wedge}2$$