QUESTION IMAGE
Question
single replacement reaction worksheet
for each reaction use the activity series to complete the reaction. if no reaction will occur, write
o reaction\. make sure you balance your final answer.
- _ ag + _ kno₃ → _ agno₃ + _ k
- _ zn + _ agno₃ → _ zn(no₃)₂ + _ ag
- _ cl₂ + _ ki → _ kcl + _ i₂
- _ ba + _ rb₂so₄ → _ rb + _ baso₄
- _ ca + _ pb(no₃)₂ → _ ca(no₃)₂ + _ pb
- _ k + _ al₂(so₄)₃ → _ k₂so₄ + _ al
- _ zn + _ pb(no₃)₂ →
- _ cl₂ + _ mgi →
- _ ca + _ agc₂h₃o₂ →
- _ al + _ pbcl₂ →
- _ br₂ + _ cai₂ →
- _ au + _ h₂so₄ →
- _ i₂ + _ sncl₂ →
- fluorine + copper (ii) chloride →
- sodium + silver hydroxide →
- hydrogen + iron (iii) oxide →
- calcium + potassium hydroxide →
- copper + nickel (ii) sulfate →
Step1: Check Activity Series
For single - replacement reactions, a metal (or non - metal) can replace another metal (or non - metal) in a compound if it is more active.
Step2: Write Reactions
- For \(Ag + KNO_3\), since \(Ag\) is less active than \(K\) (from the activity series), no reaction occurs.
- \(Zn+2AgNO_3 = Zn(NO_3)_2 + 2Ag\) ( \(Zn\) is more active than \(Ag\))
- \(Cl_2+2KI = 2KCl+I_2\) (\(Cl_2\) is more active than \(I_2\))
- \(Ba + Rb_2SO_4=BaSO_4 + 2Rb\) (\(Ba\) is more active than \(Rb\))
- \(Ca+Pb(NO_3)_2 = Ca(NO_3)_2+Pb\) (\(Ca\) is more active than \(Pb\))
- \(6K + Al_2(SO_4)_3=3K_2SO_4 + 2Al\) (\(K\) is more active than \(Al\))
- \(Zn+Pb(NO_3)_2 = Zn(NO_3)_2+Pb\) (\(Zn\) is more active than \(Pb\))
- \(Cl_2+MgI_2 = MgCl_2+I_2\) (\(Cl_2\) is more active than \(I_2\))
- \(Ca + 2AgC_2H_3O_2=Ca(C_2H_3O_2)_2+2Ag\) (\(Ca\) is more active than \(Ag\))
- \(2Al+3PbCl_2 = 2AlCl_3+3Pb\) (\(Al\) is more active than \(Pb\))
- \(Br_2+CaI_2 = CaBr_2+I_2\) (\(Br_2\) is more active than \(I_2\))
- For \(Au + H_2SO_4\), \(Au\) is less active than \(H_2\), no reaction occurs
- For \(I_2+SnCl_2\), \(I_2\) is less active than \(Cl_2\), no reaction occurs
- \(F_2+CuCl_2 = CuF_2+Cl_2\) (\(F_2\) is more active than \(Cl_2\))
- \(2Na + 2AgOH=2NaOH + 2Ag\) (\(Na\) is more active than \(Ag\))
- \(3H_2+Fe_2O_3 = 2Fe + 3H_2O\) (\(H_2\) can act as a reducing agent here, similar to a single - replacement in terms of electron transfer)
- For \(Ca+KOH\), \(Ca\) is less active than \(K\), no reaction occurs
- For \(Cu + NiSO_4\), \(Cu\) is less active than \(Ni\), no reaction occurs
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- no reaction
- \(Zn+2AgNO_3 = Zn(NO_3)_2 + 2Ag\)
- \(Cl_2+2KI = 2KCl+I_2\)
- \(Ba + Rb_2SO_4=BaSO_4 + 2Rb\)
- \(Ca+Pb(NO_3)_2 = Ca(NO_3)_2+Pb\)
- \(6K + Al_2(SO_4)_3=3K_2SO_4 + 2Al\)
- \(Zn+Pb(NO_3)_2 = Zn(NO_3)_2+Pb\)
- \(Cl_2+MgI_2 = MgCl_2+I_2\)
- \(Ca + 2AgC_2H_3O_2=Ca(C_2H_3O_2)_2+2Ag\)
- \(2Al+3PbCl_2 = 2AlCl_3+3Pb\)
- \(Br_2+CaI_2 = CaBr_2+I_2\)
- no reaction
- no reaction
- \(F_2+CuCl_2 = CuF_2+Cl_2\)
- \(2Na + 2AgOH=2NaOH + 2Ag\)
- \(3H_2+Fe_2O_3 = 2Fe + 3H_2O\)
- no reaction
- no reaction