Question

select all the correct answers.
in this reaction, how does the rate of forward reaction vary with the concentration of the product?
2h₂s(g) ⇌ 2h₂(g) + s₂(g)
it increases with an increase in the concentration of s₂(g).
it decreases with a decrease in the concentration of h₂(g).
it increases with a decrease in the concentration of h₂(g).
it decreases with an increase in the concentration of s₂(g).
it decreases with increase in the concentration of h₂(g).

Explanation:

According to Le Chatelier's principle, when the concentration of a product (\(H_2\) or \(S_2\)) increases, the system shifts to counteract that change. An increase in product concentration favors the reverse reaction (so the forward reaction rate decreases). A decrease in product (\(H_2\)) concentration favors the forward reaction (so the forward reaction rate increases).

Answer:

C. It increases with a decrease in the concentration of \(H_2(g)\).
D. It decreases with an increase in the concentration of \(S_2(g)\).
E. It decreases with increase in the concentration of \(H_2(g)\).