Question

a sample of a gas has a pressure of 1.01 atm when the volume is 256 ml. what is the pressure of the gas when the volume is 118 ml?
select the correct answer below:
2.08 atm
1.83 atm
0.466 atm
2.19 atm

Explanation:

Step1: Recall Boyle's Law

Boyle's Law states that \(P_1V_1 = P_2V_2\) (for a given amount of gas at constant temperature), where \(P_1 = 1.01\) atm, \(V_1=256\) mL, and \(V_2 = 118\) mL. We need to find \(P_2\).

Step2: Rearrange the formula to solve for \(P_2\)

From \(P_1V_1 = P_2V_2\), we can express \(P_2=\frac{P_1V_1}{V_2}\).
Substitute the values: \(P_2=\frac{1.01\times256}{118}\).
First, calculate \(1.01\times256 = 258.56\).
Then, \(\frac{258.56}{118}\approx2.19\) (using division operation).

Answer:

\(2.19\) atm (the fourth option)