Question

a sample of f₂ gas occupies 1.120 l when held at 273.15 k. what was the original volume, in ml, occupied by the gas when the temperature was -75.0°c?
○ 1540 ml
○ 308 ml
○ 4080 ml
○ 812 ml

Explanation:

Step1: Convert temperatures to Kelvin

The initial temperature \( T_1 = -75.0^\circ \text{C} + 273.15 = 198.15 \, \text{K} \).
The final temperature \( T_2 = 273.15 \, \text{K} \), and final volume \( V_2 = 1.120 \, \text{L} = 1120 \, \text{mL} \).

Step2: Apply Charles's Law (\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\))

Rearrange to solve for \( V_1 \): \( V_1 = V_2 \times \frac{T_1}{T_2} \).
Substitute values: \( V_1 = 1120 \, \text{mL} \times \frac{198.15 \, \text{K}}{273.15 \, \text{K}} \).
Calculate: \( \frac{198.15}{273.15} \approx 0.7254 \), then \( V_1 \approx 1120 \times 0.7254 \approx 812 \, \text{mL} \).

Answer:

812 mL (corresponding to the option "812 mL")