Question

a sample of co₂ gas is placed in a 125ml flask where it exerts a pressure of 67.5 mmhg. what is the pressure of this gas sample when it is transferred to a 500ml flask at the same temperature?

Explanation:

Step1: Write down Boyle's Law

Boyle's Law states that \(P_1V_1 = P_2V_2\) (at constant temperature, for a fixed amount of gas). Here, \(P_1 = 67.5\ mmHg\), \(V_1=125\ mL\), and \(V_2 = 500\ mL\). We need to find \(P_2\).

Step2: Rearrange the formula to solve for \(P_2\)

From \(P_1V_1 = P_2V_2\), we can get \(P_2=\frac{P_1V_1}{V_2}\).
Substitute the values: \(P_2=\frac{67.5\ mmHg\times125\ mL}{500\ mL}\)

$$P_2=\frac{67.5\times125}{500}\ mmHg$$

$$P_2=\frac{8437.5}{500}\ mmHg = 16.875\ mmHg$$

Answer:

\(16.875\ mmHg\)