Question

a sample of ca(c₂h₃o₂)₂ is found to contain 40.08 g of ca, 48.04 g of c, 6.06 of g of h, and 64.00 g of o. what is the percent composition of ca in the compound? % ca

Explanation:

Step1: Calculate the total mass of the compound

Add the masses of all elements: $40.08 + 48.04+6.06 + 64.00$.
$$40.08 + 48.04+6.06 + 64.00=158.18\ \text{g}$$

Step2: Calculate the percent composition of Ca

Use the formula $\text{Percent Composition}=\frac{\text{Mass of Element}}{\text{Total Mass of Compound}}\times100\%$.
For Ca: $\frac{40.08}{158.18}\times 100\%$.
$$\frac{40.08}{158.18}\times 100\%\approx 25.34\%$$

Answer:

$25.34$