Question

room a: maintained at 18°c (64°f)
room b: heated to 28°c (82°f)
in each room, liam places an open bottle of vanilla extract and uses sensors to measure how quickly and how far the vanilla scent molecules spread.
how will the vanilla scent spread differently in the warm room compared to the cool room?
a. the scent will spread faster and farther in the warm room.
b. the scent will spread faster and farther in the cool room.
c. the scent will spread the same in both rooms.
d. the scent wont spread at all in the warm room.

Explanation:

According to the kinetic - molecular theory, as temperature increases, the kinetic energy of molecules increases. In the warm room (Room B at \(28^{\circ}C\)), the vanilla scent molecules have more kinetic energy. This means they move faster (higher speed of diffusion) and can cover more distance (spread farther) compared to the cooler room (Room A at \(18^{\circ}C\)) where the molecules have less kinetic energy and thus move more slowly and don't spread as far or as quickly.

Answer:

A. The scent will spread faster and farther in the warm room.