Question

reversible reactions and equilibrium
pre - test complete
1 2 3 4 5 6
consider the general reversible reaction.
aa + bb ←→ cc + dd
what is the equilibrium constant expression for the given system?
○ ( k_{eq}=\frac{ccdd}{aabb} )
○ ( k_{eq}=\frac{cd}{ab} )
○ ( k_{eq}=\frac{a^ab^b}{c^cd^d} )
○ ( k_{eq}=\frac{c^cd^d}{a^ab^b} )
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Explanation:

The equilibrium constant \(K_{eq}\) for a general reversible reaction \(aA + bB
ightleftharpoons cC + dD\) is calculated by taking the product of the concentrations of the products (\([C]^c[D]^d\)) divided by the product of the concentrations of the reactants (\([A]^a[B]^b\)). The exponents \(a,b,c,d\) are the stoichiometric coefficients from the balanced chemical equation.

Answer:

\(K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}\) (the fourth option in the given choices)