Question

a reaction of 22.85 g of sodium hydroxide with 20.82 g of hydrogen chloride produces 10.29 g of water and some mass of sodium chloride. how many grams of sodium chloride were produced in the chemical reaction?
____ g sodium chloride

Explanation:

Step1: Apply the law of conservation of mass

The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.
The mass of reactants is \(m_{reactants}=m_{NaOH}+m_{HCl}\), where \(m_{NaOH} = 22.85\space g\) and \(m_{HCl}=20.82\space g\). So \(m_{reactants}=22.85 + 20.82=43.67\space g\).
The mass of products is \(m_{products}=m_{H_2O}+m_{NaCl}\), where \(m_{H_2O} = 10.29\space g\) and \(m_{NaCl}\) is the mass we want to find.

Step2: Solve for the mass of sodium chloride

Since \(m_{reactants}=m_{products}\), we have \(m_{NaCl}=m_{reactants}-m_{H_2O}\).
Substitute the values: \(m_{NaCl}=43.67 - 10.29\).
\(m_{NaCl}=33.38\space g\)

Answer:

\(33.38\)